Before I start explaining the complex format, here is how sumproduct was meant to do
Assuming there are 2 sets of numbers as follows:
A B
1 6 10
2 3 5
When you entered the Excel Function =SUMPRODUCT(A1:A2,B1:B2) into one of the cells, say D1, you get a result of 75. What the excel function does is that it will multiply A1 with B1 (6 x 10) and A2 with B2 (3 x 5). After which, it will add up the 2 results and give you 75 (60 + 15).
A
1. Excel
2. VBA
3. Internet Marketing
4. What is a Blog
5. What is a Blog
6. Internet Marketing
7. What is a Blog
8. VBA
In our unique list, the formula initially started as simple as this =sumproduct(1/countif(A1:A8,A1:A8)).
What the countif [countif(A1:A8,A1:A8)]does is actually a shortcut way of populating the formula [=countif(A1:A8,A1)] in B1 and copy the formula all the way down to B8. The results would have been: 1 count of the word Excel (which appears in A1) is found in the list, 2 counts of VBA is found in the list, etc. As the function is inversed, the result turns out to be like this:
A B
1. Excel 1/1
2. VBA 1/2
3. Internet Marketing 1/2
4. What is a Blog 1/3 (1/3 because there is 3 counts of the phrase "What is a blog")
5. What is a Blog 1/3
6. Internet Marketing 1/2
7. What is a Blog 1/3
8. VBA 1/2
As a result, the number of unique records are returned,
Excel = 1/1 = 1
VBA = 1/2 + 1/2 = 1
Internet marketing = 1/2 + 1/2 = 1
What is a Blog = 1/3 + 1/3 + 1/3 =1
The total is 4 unique records.
This works perfect provided that the list do not contains blank records. If not, the result 1 divided by 0 would have returned a #div/0! error To circumvent that, the following are added. 1 is changed to [A1:A8<>""] to tell the formula to ignore blank records.
Likewise, the following [(A1:A100="")] is added to make sure that denominator will return a value greater than 0. In this case, when the list contains more than a blank record, the denominator is more than 0 because of this segment of the formula + (A1:A100=""). If the list do not contain any 0, it will still return a number based on the formula COUNTIF(A1:A100,A1:A100). Either way, the denominator will return a value of more than 0.